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which always gives a positive value.

· | x – 1 | < 0

· | x + 1 | + | x | < 2 x

· | x + 2 | < 2

· | x + 3 | > 2

Case 1: - +(x – 3) > 6

x – 3 > 6

x> 6 + 3

Case 2: - - (x – 3) > 6

(x – 3) < - 6

x< 3 – 6

Case 1: - + (x - 1) < 2x

X – 2 x < 1

- x< 1

x > -1

Case 2: - - (x - 1) < 2x

(x - 1) > - 2x

x+ 2x >1

3 x >1

x> 1/3

Case 1: - + (2x) < 2 so,

Case 2: - - (2x) < 2 or, 2 x > - 2 so,

Therefore -1 < x < 1