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Solve (2x -3y-7z) + (11z-12y+14x).

Now we begin by opening both the parentheses

= 2x-3y-7z+11z-12y+14x

Now we will separate the like terms and writing them together, so we have

= 2x+14x-3y-12y-7z+11z

=16x-15y+4z

Hence 16x-15y+4z is the solution of (2x -3y-7z) + (11z-12y+14x).

(3x + 4y) (2x-11y).

In this case, the absence of any sign between the parentheses invariably means multiplication.

It means that the numbers in the first parentheses will multiply individually with all the numbers inside the 2

Therefore the above expression can thus be solved as follows:

(3x + 4y)(2x-11y)

= 3x X 2x + 3x X-11y +4yX2x +4yX-11y

= 6x² -33xy+8xy-44y² (-33xy and 8xy being like terms can be added together)

On further solving, it will become:-

= 6x²-25xy-44y²

Hence 6x²-25xy-44y² is the required solution of the problem (3x + 4y) (2x-11y).